From 8b9bb9346c217874670b0f1798ab6f1cb28fdb83 Mon Sep 17 00:00:00 2001 From: Justin Gassner Date: Tue, 20 Feb 2024 12:01:07 +0100 Subject: Update --- .../functional-analysis-basics/reflexive-spaces.md | 30 +++++++++++++++++++--- 1 file changed, 26 insertions(+), 4 deletions(-) (limited to 'pages/functional-analysis-basics/reflexive-spaces.md') diff --git a/pages/functional-analysis-basics/reflexive-spaces.md b/pages/functional-analysis-basics/reflexive-spaces.md index 58ca1d3..69fefc4 100644 --- a/pages/functional-analysis-basics/reflexive-spaces.md +++ b/pages/functional-analysis-basics/reflexive-spaces.md @@ -1,7 +1,9 @@ --- title: Reflexive Spaces parent: Functional Analysis Basics -nav_order: 2 +nav_order: 4 +description: > + A normed space is said to be reflexive if the canonical embedding into its bidual is surjective. --- # {{ page.title }} @@ -28,10 +30,30 @@ The canonical embedding $C : X \to X''$ of a normed space into its bidual is well-defined and an embedding of normed spaces. {% endlemma %} +In particular, $C$ is isometric, hence injective. + {% proof %} -{% endproof %} +We have to show that, for any given $x \in X$, +$g_x$ is a bounded linear functional on $X'$. +Linearity follows from the fact that +the vector space structure on $X'$ is given by pointwise operations. +To see that $g_x$ is bounded, observe that -In particular, $C$ is isometric, hence injective. +$$ +\abs{g_x(f)} = \abs{f(x)} \le \norm{f} \norm{x} +$$ + +holds for all $f \in X'$. +Moreover, this implies that $\norm{g_x} \le \norm{x}$. +Thanks to +[Hahn–Banach](/pages/functional-analysis-basics/the-fundamental-four/hahn-banach-theorem.html#hahn-banach-theorem-existence-of-functionals), +we know that there exists a bounded linear functional +$f \in X'$ with $\norm{f} = 1$ such that $f(x) = \norm{x}$; +hence, $\norm{g_x} = \norm{x}$. +This means that the mapping $x \mapsto g_x$ is isometric. +Clearly, this mapping is also linear, and thus an embedding +of normed spaces. +{% endproof %} {% definition Reflexivity %} A normed space is said to be *reflexive* @@ -40,7 +62,7 @@ is surjective. {% enddefinition %} If a normed space $X$ is reflexive, -then $X$ is isomorphic with $X''$, its bidual. +then $X$ is isometrically isomorphic with $X''$, its bidual. James gives a counterexample for the converse statement. {% theorem %} -- cgit v1.2.3-54-g00ecf